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(D) For a common emitter amplifier,the voltage gain $(A_v)$ is given by the formula: $A_v = \beta 	imes \frac{R_C}{R_B}$,where $\beta$ is the current

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$4 : 1$

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(D) For a common emitter amplifier,the voltage gain $(A_v)$ is given by the formula: $A_v = \beta 	imes \frac{R_C}{R_B}$,where $\beta$ is the current amplification factor,$R_C$ is the collector resistance,and $R_B$ is the base resistance.Given that the ratio of voltage gain $(A_v)$ to the current amplification factor $(\beta)$ is $4$,we have: $\frac{A_v}{\beta} = 4$.Substituting the expression for $A_v$ into the given ratio: $\frac{\beta 	imes (R_C / R_B)}{\beta} = 4$.This simplifies to: $\frac{R_C}{R_B} = 4$.Therefore,the ratio of the collector resistance to the base resistance is $4 : 1$.

In a common emitter amplifier of a transistor,if the ratio of the voltage gain and current amplification factor is $4$,then the ratio of the collector and base resistances is

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