In a transistor amplifier, $\beta = 62$, $R_L = 5 \times 10^3 \ \Omega$, and the input resistance is $500 \ \Omega$. The ratio of power gain to voltage gain is .......

  • A
    $60$
  • B
    $61$
  • C
    $62$
  • D
    $100$

Explore More

Similar Questions

In a transistor amplifier,the voltage gain is

For the given bipolar junction transistor,find the approximate value of $I_B$,if $V_{CC} = 9 \ V$,$V_{BB} = 1.5 \ V$,$R_C = 13 \ k\Omega$,$R_E = 17 \ k\Omega$,and $\beta = 100$. (Assume the transistor is in active mode and $V_{BE} = 0.7 \ V$)

Difficult
View Solution

In a $CE$ transistor amplifier,the signal voltage across the collector resistance is $2.5 \ V$. The input signal voltage is $0.02 \ V$. If the base and collector resistances are $1.5 \ k\Omega$ and $2.5 \ k\Omega$,then the current amplification factor is

Consider an $NPN$ transistor amplifier in common-emitter configuration. The current gain of the transistor is $100$. If the collector current changes by $1\, mA$,what will be the change in emitter current in $mA$?

In an amplifier circuit,the value of the load resistance $R_L$ is $2 \text{ k}\Omega$. $A$ change of $10 \text{ }\mu\text{A}$ in the base current of the transistor results in a change of $1 \text{ mA}$ in the collector current. The change in the collector-emitter voltage $(V_{CE})$ is ....... $V$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo