For the given Common Emitter (CE) transistor | vedclass

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(A) Given:Base current $I_B = 0.04 	ext{ mA} = 0.04 	imes 10^{-3} 	ext{ A}$Collector current gain $\beta = 100$Supply voltage $V_{CC} = 20 	ext{ V

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(A) Given:Base current $I_B = 0.04 	ext{ mA} = 0.04 	imes 10^{-3} 	ext{ A}$Collector current gain $\beta = 100$Supply voltage $V_{CC} = 20 	ext{ V}$Collector-emitter voltage $V_{CE} = 12 	ext{ V}$First,calculate the collector current $I_C$ using the relation:$I_C = \beta 	imes I_B$$I_C = 100 	imes 0.04 	imes 10^{-3} 	ext{ A} = 4 	imes 10^{-3} 	ext{ A} = 4 	ext{ mA}$Now,apply Kirchhoff's Voltage Law to the collector circuit:$V_{CC} = I_C R_C + V_{CE}$$R_C = \frac{V_{CC} - V_{CE}}{I_C}$$R_C = \frac{20 	ext{ V} - 12 	ext{ V}}{4 	imes 10^{-3} 	ext{ A}}$$R_C = \frac{8}{4 	imes 10^{-3}} \Omega = 2 	imes 10^3 \Omega = 2 	ext{ k}\Omega$Thus,the value of $R_C$ is $2 	ext{ k}\Omega$.

For the given Common Emitter $(CE)$ transistor circuit,the base current is $I_B = 0.04 \text{ mA}$. If the current gain $\beta = 100$ and the collector-emitter voltage $V_{CE} = 12 \text{ V}$,find the value of the collector resistance $R_C$ in $\text{k}\Omega$.

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