In common emitter mode of a transistor, the d | vedclass

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(B) Given:Common emitter current gain, $\beta = 20$Emitter current, $I_E = 7 	ext{ mA}$We know the relationship between emitter current and collector

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$20$

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(B) Given:Common emitter current gain, $\beta = 20$Emitter current, $I_E = 7 	ext{ mA}$We know the relationship between emitter current and collector current in common emitter mode is $I_E = I_C + I_B$.Also, $\beta = I_C / I_B$, which implies $I_B = I_C / \beta$.Substituting $I_B$ in the first equation:$I_E = I_C + (I_C / \beta) = I_C(1 + 1/\beta) = I_C((\beta + 1) / \beta)$.Rearranging for $I_C$:$I_C = I_E 	imes (\beta / (\beta + 1))$.Substituting the values:$I_C = 7 	imes (20 / (20 + 1)) = 7 	imes (20 / 21)$.$I_C = 7 	imes (20 / 21) = 20 / 3 	ext{ mA}$.

In common emitter mode of a transistor, the d.c. current gain $(\beta)$ is $20$ and the emitter current $(I_E)$ is $7 \text{ mA}$. The collector current $(I_C)$ is: (in $/3 \text{ mA}$)

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