A point source is placed at a distance of 15 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For the lens: $u = -15 \, cm$,$f = +10 \, cm$. Using the lens formula: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f} \implies \frac{1}{v} - \frac{1}{-1

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) For the lens: $u = -15 \, cm$,$f = +10 \, cm$. Using the lens formula: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f} \implies \frac{1}{v} - \frac{1}{-15} = \frac{1}{10} \implies \frac{1}{v} = \frac{1}{10} - \frac{1}{15} = \frac{3-2}{30} = \frac{1}{30}$. So,$v = 30 \, cm$. For the image to form on the object itself,the rays must strike the convex mirror normally. This happens if the rays are directed towards the center of curvature of the mirror. The distance of the image from the lens is $30 \, cm$. The mirror is placed at a distance $d$ from the lens. The distance of the mirror from the image formed by the lens is $(30 - d)$. For the rays to be normal to the mirror,this distance must be equal to the radius of curvature $R = 2f = 2 	imes 12 = 24 \, cm$. Therefore,$30 - d = 24 \implies d = 6 \, cm$.

$A$ point source is placed at a distance of $15 \, cm$ from a converging (convex) lens of focal length $10 \, cm$. At what distance (in $cm$) should a convex mirror of focal length $12 \, cm$ be placed so that the image is formed on the object itself?

Similar Questions

$A$ convex mirror and a concave mirror of radius $10\; cm$ each are placed $15\; cm$ apart facing each other. An object is placed midway between them. If the reflection first takes place in the concave mirror and then in the convex mirror,the position of the final image is:

$A$ ray of light strikes a plane mirror $M$ at an angle of $45^{\circ}$ as shown in the figure. After reflection,the ray passes through a prism of refractive index $1.5$ whose apex angle is $4^{\circ}$. The total angle through which the ray is deviated is......$^{\circ}$

Which of the following can form a diminished,virtual,and erect image of your face?

Amount of light entering into the camera depends upon

$A$ cube of side $2\, m$ is placed in front of a concave mirror of focal length $1\, m$ with its face $P$ at a distance of $3\, m$ and face $Q$ at a distance of $5\, m$ from the mirror. The distance between the images of face $P$ and $Q$ and the heights of the images of $P$ and $Q$ are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module