The angle of minimum deviation is equal to the angle of the equilateral prism. At what angle of incidence $i$ will this minimum deviation occur?

$A$ ray of light suffers minimum deviation when incident on a prism having an angle of the prism equal to $60^{\circ}$. The refractive index of the prism material is $\sqrt{2}$. The angle of incidence (in degrees) is . . . . . . .

The principal section of a glass prism is an isosceles triangle $ABC$ with $AB = AC$. The face $AC$ is silvered. $A$ ray of light is incident normally on the face $AB$ and after two reflections, it emerges from the base $BC$ perpendicular to the base. The angle $BAC$ of the prism is: (in $^{\circ}$)

$A$ prism $(\mu=1.5)$ has a refracting angle of $30^{\circ}$. The deviation of a monochromatic ray incident normally on one of its surfaces will be (given,$\sin 48^{\circ} 36^{\prime}=0.75$):

The angle of minimum deviation for a prism is $40^o$ and the angle of the prism is $60^o$. The angle of incidence in this position will be.....$^o$

$A$ thin prism of refracting angle $2^o$ deviates an incident ray through an angle of $1^o$. Find the value of the refractive index of the material of the prism.