What is the maximum distance at which an imag | vedclass

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(B) For a convex mirror,the focal length $f$ is positive $(f = +10 \ cm)$.The mirror formula is $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.As the objec

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$10 \ cm$

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(B) For a convex mirror,the focal length $f$ is positive $(f = +10 \ cm)$.The mirror formula is $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.As the object distance $u$ varies from $-\infty$ to $0$,the image distance $v$ varies from $f$ to $0$.Specifically,when the object is at infinity $(u = -\infty)$,the image is formed at the focus $(v = f = 10 \ cm)$.When the object is at the pole $(u = 0)$,the image is formed at the pole $(v = 0)$.Therefore,the image always forms between the pole and the focus of the convex mirror.The maximum distance of the image from the mirror is equal to the focal length,which is $10 \ cm$.

What is the maximum distance at which an image can be formed by a convex mirror of focal length $10 \ cm$?

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Assertion : The formula connecting $u, v$ and $f$ for a spherical mirror is valid only for mirrors whose sizes are very small compared to their radii of curvature.
Reason : Laws of reflection are strictly valid for plane surfaces,but not for large spherical surfaces.

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