For a given medium,the polarizing angle is $60^{\circ}$. The critical angle for this medium is . . . . . .

The refractive index of a medium is $\sqrt{3}$. If unpolarised light is incident on it at the polarizing angle of the medium,then the angle of refraction is......$^o$

$A$ beam of light strikes a piece of glass at an angle of incidence of $60^{\circ}$ and the reflected beam is completely plane-polarized. The refractive index of glass is

If the polarizing angle for a medium is $60^\circ$,then the critical angle for that medium is . . . . . .

$A$ solid glass sphere of refractive index $n=\sqrt{3}$ and radius $R$ contains a spherical air cavity of radius $\frac{R}{2}$,as shown in the figure. $A$ very thin glass layer is present at the point $O$ so that the air cavity (refractive index $n=1$) remains inside the glass sphere. An unpolarized,unidirectional and monochromatic light source $S$ emits a light ray from a point inside the glass sphere towards the periphery of the glass sphere. If the light is reflected from the point $O$ and is fully polarized,then the angle of incidence at the inner surface of the glass sphere is $\theta$. The value of $\sin \theta$ is

The refractive index of a material is equal to the tangent of the polarising angle. This is called: