The refractive index of glass for red light is $1.520$ and for blue light is $1.525$. Let $D_1$ and $D_2$ be the angles of deviation for red and blue light,respectively,in a prism of this glass. Then:

What is the maximum value of the refractive index of the material of a prism with prism angle $A$ such that light can pass through it?

The refracting angle of a glass prism is $30^{\circ}$. $A$ ray is incident on one of the faces and is perpendicular to it. The angle of deviation $\delta$ between the incident ray and the ray that leaves the prism is (Refractive index of glass $= 1.5$) (Given: $\sin(30^{\circ}) = 0.5, \sin(48.6^{\circ}) = 0.75$). (in $^{\circ}$)

The angle of deviation $\delta$ produced by a prism of refractive index $\mu$ and small refracting angle $A$ is given by:

How is the graph between the angle of deviation $(\delta)$ and the angle of incidence $(i)$ represented for a triangular prism?

$A$ prism with refractive index $\mu = 1.5$ has a prism angle of $30^\circ$. If a ray is incident normally on one surface,calculate its deviation. (Given: $\sin(48^\circ 36') = 0.75$)