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(B) Since the wires are connected in parallel,the potential difference $V$ across both wires is the same.Using Ohm's Law,$I = V/R$,where $R = \rho \el

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$1/3$

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(B) Since the wires are connected in parallel,the potential difference $V$ across both wires is the same.Using Ohm's Law,$I = V/R$,where $R = ho \ell / A = ho \ell / (\pi r^2)$.Therefore,the ratio of currents is $\frac{I_1}{I_2} = \frac{R_2}{R_1} = \frac{ho \ell_2 / (\pi r_2^2)}{ho \ell_1 / (\pi r_1^2)} = \frac{\ell_2}{\ell_1} 	imes \left( \frac{r_1}{r_2} ight)^2$.Given $\frac{\ell_1}{\ell_2} = \frac{4}{3}$ and $\frac{r_1}{r_2} = \frac{2}{3}$.Substituting these values: $\frac{I_1}{I_2} = \frac{3}{4} 	imes \left( \frac{2}{3} ight)^2 = \frac{3}{4} 	imes \frac{4}{9} = \frac{1}{3}$.

Two wires of the same material are connected in parallel to a circuit. If the ratio of their lengths is $4/3$ and the ratio of their radii is $2/3$,then the ratio of the electric current flowing through the wires will be .......

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