In a Wheatstone bridge,three resistors P,Q,an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a balanced Wheatstone bridge,the ratio of resistances in adjacent arms must be equal: $\frac{P}{Q} = \frac{R}{S_{eq}}$,where $S_{eq}$ is the e

Vedclass · Accepted Answer

$\frac{P}{Q} = \frac{R(S_1 + S_2)}{S_1 S_2}$

Vedclass · Answer

(B) For a balanced Wheatstone bridge,the ratio of resistances in adjacent arms must be equal: $\frac{P}{Q} = \frac{R}{S_{eq}}$,where $S_{eq}$ is the equivalent resistance of the fourth arm.Since $S_1$ and $S_2$ are connected in parallel,their equivalent resistance is given by $S_{eq} = \frac{S_1 S_2}{S_1 + S_2}$.Substituting this into the balance condition,we get: $\frac{P}{Q} = \frac{R}{(\frac{S_1 S_2}{S_1 + S_2})}$.Simplifying this,we obtain: $\frac{P}{Q} = \frac{R(S_1 + S_2)}{S_1 S_2}$.

In a Wheatstone bridge,three resistors $P$,$Q$,and $R$ are connected in three arms,and the fourth arm is formed by the parallel combination of two resistors $S_1$ and $S_2$. The condition for the bridge to be balanced is:

Similar Questions

In the circuit given,the correct relation for a balanced Wheatstone bridge is

In the following circuit,find the current through the path $ACB$ if each resistance $R = 4 \ \Omega$ and the battery voltage is $16 \ V$. (in $A$)

The figure shows a network of currents. The magnitude of currents is shown in the diagram. The current $i$ will be ................. $A$.

The Wheatstone bridge shown in the diagram is balanced. If $P_3$ is the power dissipated by $R_3$ and $P_1$ is the power dissipated by $R_1$,then the ratio $\frac{P_3}{P_1}$ is

The figure shows a network of currents. The values of the currents are shown in the figure. What is the value of current $I$ in $A$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module