If the ammeter in the given figure shows a re | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The resistors $3 \, \Omega$ and $6 \, \Omega$ are connected in parallel. Their equivalent resistance $R_p$ is given by:$R_p = \frac{3 	imes 6}{3

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) The resistors $3 \, \Omega$ and $6 \, \Omega$ are connected in parallel. Their equivalent resistance $R_p$ is given by:$R_p = \frac{3 	imes 6}{3 + 6} = \frac{18}{9} = 2 \, \Omega$This equivalent resistance $R_p$ is in series with the resistor $R$. The total resistance of the circuit is $R_{eq} = R_p + R = 2 + R$.According to Ohm's law,the total current $I$ in the circuit is given by $I = \frac{V}{R_{eq}}$.Given $I = 2 \, A$ and $V = 6 \, V$,we have:$2 = \frac{6}{2 + R}$$2 + R = \frac{6}{2} = 3$$R = 3 - 2 = 1 \, \Omega$

If the ammeter in the given figure shows a reading of $2 \, A$,find the value of $R$ in $\Omega$.

Similar Questions

An ammeter and a voltmeter of resistance $R$ are connected in series to an electric cell of negligible internal resistance. Their readings are $A$ and $V$ respectively. If another resistance $R$ is connected in parallel with the voltmeter, what happens to the readings $A$ and $V$?

For the given circuit diagram,if the dissipated electrical power is $150 \text{ W}$,find the value of resistance $R$. (in $\Omega$)

For what value of resistance $R$ in the given circuit will the galvanometer reading be zero (in $\Omega$)? The internal resistance of both batteries is negligible.

For the given circuit,in the steady state,$\left| V_{B}-V_{D}\right| = .......V.$

Find the value of the current from the battery in the circuit shown in the figure. (in $A$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module