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(D) The phase difference $\phi$ between the waves originating from the top and bottom edges of a slit of width $d$ is given by $\phi = \frac{2\pi}{\la

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$2\pi \, rad$

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(D) The phase difference $\phi$ between the waves originating from the top and bottom edges of a slit of width $d$ is given by $\phi = \frac{2\pi}{\lambda} (d \sin 	heta)$.For the first minimum in a single-slit diffraction pattern,the condition is $d \sin 	heta = \lambda$.Substituting this condition into the phase difference formula:$\phi = \frac{2\pi}{\lambda} (\lambda) = 2\pi \, rad$.Thus,the phase difference between the waves from the top and bottom edges at the first minimum is $2\pi \, rad$.

$A$ plane wavefront of monochromatic light is incident normally on a narrow slit. $A$ diffraction pattern is formed on a screen. What is the phase difference between the waves originating from the top and bottom edges of the slit at the position of the first minimum?

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