Light of wavelength $6328 \, \mathring{A}$ is incident on a slit of width $0.2 \, mm$. Find the angular width of the central maximum on a screen at a distance of $9 \, m$ in degrees.

In a diffraction experiment from a single slit,the angular width of the central maximum does $NOT$ depend upon:

If a narrow slit of width $2 \, mm$ is illuminated by monochromatic light of wavelength $500 \, nm$,then the distance between the first minima on both sides on a screen at a distance of $1 \, m$ is ....... $mm$.

The first minima due to a single slit diffraction is at $\theta = 30^o$ for a light of wavelength $5000 \, \mathring{A}$. The width of the slit is

The waves of $600 \ \mu m$ wavelength are incident normally on a slit of $1.2 \ mm$ width. The value of diffraction angle corresponding to the first minima will be (in radian) -

Explain diffraction by a single slit.