In a Young's double-slit experiment,the slit | vedclass

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(B) The condition for constructive interference (maxima) in a Young's double-slit experiment is given by $d \sin 	heta = n \lambda$,where $d$ is the

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$\sin^{-1} (3 	imes 10^{-6})$

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(B) The condition for constructive interference (maxima) in a Young's double-slit experiment is given by $d \sin 	heta = n \lambda$,where $d$ is the slit separation,$	heta$ is the angular position,$n$ is the order of the maximum,and $\lambda$ is the wavelength.Given: $d = 0.589 \, mm = 0.589 	imes 10^{-3} \, m$,$\lambda = 589 \, nm = 589 	imes 10^{-9} \, m$,and $n = 3$.Substituting the values into the formula:$0.589 	imes 10^{-3} \sin 	heta = 3 	imes 589 	imes 10^{-9}$$\sin 	heta = \frac{3 	imes 589 	imes 10^{-9}}{0.589 	imes 10^{-3}}$$\sin 	heta = \frac{3 	imes 589 	imes 10^{-9}}{589 	imes 10^{-6}}$$\sin 	heta = 3 	imes 10^{-3} 	imes 10^{-3} = 3 	imes 10^{-6}$Therefore,$	heta = \sin^{-1} (3 	imes 10^{-6})$.

In a Young's double-slit experiment,the slit separation is $0.589 \, mm$ using sodium light. What is the angular separation between the third maximum and the central maximum? $(\lambda = 589 \, nm)$

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