A combination of two prisms,one of flint glas | vedclass

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(C) Given: $A = 15^o, \omega = 0.03, \omega' = 0.02, \mu = 1.65, \mu' = 1.52$.For dispersion without deviation,the net deviation $\delta + \delta' = 0

Vedclass · Accepted Answer

$0.0975$

Vedclass · Answer

(C) Given: $A = 15^o, \omega = 0.03, \omega' = 0.02, \mu = 1.65, \mu' = 1.52$.For dispersion without deviation,the net deviation $\delta + \delta' = 0$.$(\mu - 1)A + (\mu' - 1)A' = 0$$(1.65 - 1)15^o + (1.52 - 1)A' = 0$$0.65 	imes 15^o + 0.52 	imes A' = 0$$A' = -\frac{0.65 	imes 15^o}{0.52} = -18.75^o$.The negative sign indicates that the prisms are placed in opposition.Net angular dispersion $	heta = \delta_v - \delta_r = \omega(\mu - 1)A + \omega'(\mu' - 1)A'$.Substituting the values:$	heta = 0.03(1.65 - 1)15^o + 0.02(1.52 - 1)(-18.75^o)$$	heta = 0.03(0.65)(15^o) + 0.02(0.52)(-18.75^o)$$	heta = 0.2925^o - 0.195^o = 0.0975^o$.

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