If the $5^{th}$ term of a geometric progression is $2$,what is the product of its first $9$ terms?

  • A
    $256$
  • B
    $512$
  • C
    $1024$
  • D
    None of these

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Let $A_n = \left( \frac{3}{4} \right) - \left( \frac{3}{4} \right)^2 + \left( \frac{3}{4} \right)^3 - \dots + (-1)^{n-1} \left( \frac{3}{4} \right)^n$ and $B_n = 1 - A_n$. Then,the least odd natural number $p$ such that $B_n > A_n$ for all $n \geq p$ is:

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