In how many ways can $5$ boys and $5$ girls be seated around a circular table such that no two girls are together?

$A$ family consisting of a mother,father,and their $8$ children ($4$ boys and $4$ girls) are to be seated at a round table in a party. How many ways can this be done if the mother and father sit together and the males and females alternate?

The number of ways in which $6$ boys and $4$ girls can be seated around a round table such that $2$ special boys and a special girl never sit together is

The number of ways,in which $5$ girls and $7$ boys can be seated at a round table so that no two girls sit together,is

The number of ways in which $5$ boys and $4$ girls can sit around a circular table such that no two girls sit together is:

$21$ friends were invited for a party. Two round tables can accommodate $12$ and $9$ friends respectively. The number of ways of the seating arrangements of friends is: