If the statement (p vee sim r) rightarrow (q | vedclass

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(C) Given that the implication $(p \vee \sim r) \rightarrow (q \wedge r)$ is false.An implication $A \rightarrow B$ is false only when $A$ is true and

Vedclass · Accepted Answer

Either true or false

Vedclass · Answer

(C) Given that the implication $(p \vee \sim r) ightarrow (q \wedge r)$ is false.An implication $A ightarrow B$ is false only when $A$ is true and $B$ is false.Therefore,$(p \vee \sim r)$ is true and $(q \wedge r)$ is false.Since $(q \wedge r)$ is false and $q$ is true,$r$ must be false.Now,substitute $r = 	ext{False}$ into $(p \vee \sim r) = 	ext{True}$.$(p \vee \sim 	ext{False}) = 	ext{True} \Rightarrow (p \vee 	ext{True}) = 	ext{True}$.Since $(p \vee 	ext{True})$ is always true regardless of the value of $p$,$p$ can be either true or false.

If the statement $(p \vee \sim r) \rightarrow (q \wedge r)$ is false and the statement $q$ is true,then what is the truth value of statement $p$?

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