What is the range of values for $\frac{x}{x^2 + 4}$ for all real values of $x$?
- A$\frac{-1}{2} \le y \le \frac{1}{2}$
- B$\frac{-1}{4} \le y \le \frac{1}{4}$
- C$\frac{-1}{6} \le y \le \frac{1}{6}$
- DNone of these
Explore More
Similar Questions
The domain of the function $f(x) = \sqrt{\frac{x-7}{9-x}}$ is
MediumKCET 2026
View SolutionLet $f: R \rightarrow R$ be defined by $f(x) = \frac{1}{x}$ for all $x \in R$. Then $f$ is:
MediumKCET 2015
View SolutionRange of the function $f(x) = \frac{x^2+x+2}{x^2+x+1}, x \in R$ is
Find the range of the following function:
$f(x) = x$,where $x$ is a real number.
$f(x) = x$,where $x$ is a real number.
Easy
View SolutionThe domain of the function $f(x) = \frac{1}{\sqrt{x+|x|}}$ is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo