For how many values of a does the equation (a | vedclass

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(A) For the given equation $(a^2 - 3a + 2)x^2 + (a^2 - 4)x + a^2 - a - 2 = 0$ to be a linear equation,the coefficient of $x^2$ must be zero,while the

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$1$

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(A) For the given equation $(a^2 - 3a + 2)x^2 + (a^2 - 4)x + a^2 - a - 2 = 0$ to be a linear equation,the coefficient of $x^2$ must be zero,while the coefficient of $x$ must not be zero.Step $1$: Set the coefficient of $x^2$ to zero.$a^2 - 3a + 2 = 0$$(a - 1)(a - 2) = 0$So,$a = 1$ or $a = 2$.Step $2$: Check the condition for $x$ coefficient $(a^2 - 4) 
eq 0$ for these values.If $a = 1$: Coefficient of $x$ is $(1)^2 - 4 = -3 
eq 0$. This is valid.If $a = 2$: Coefficient of $x$ is $(2)^2 - 4 = 0$. This makes the equation $0x^2 + 0x + (4 - 2 - 2) = 0$,which is $0 = 0$. This is not a linear equation.Thus,only $a = 1$ satisfies the condition.

For how many values of $a$ does the equation $(a^2 - 3a + 2)x^2 + (a^2 - 4)x + a^2 - a - 2 = 0$ become a linear equation?

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