If the roots of the equation (b - c)x^2 + (c | vedclass

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(C) Given the quadratic equation $(b - c)x^2 + (c - a)x + (a - b) = 0$. Since the roots are equal,the discriminant $D = 0$. Here,$A = (b - c)$,$B = (c

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Arithmetic Progression

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(C) Given the quadratic equation $(b - c)x^2 + (c - a)x + (a - b) = 0$. Since the roots are equal,the discriminant $D = 0$. Here,$A = (b - c)$,$B = (c - a)$,and $C = (a - b)$. $D = B^2 - 4AC = (c - a)^2 - 4(b - c)(a - b) = 0$. Expanding this: $(c^2 - 2ac + a^2) - 4(ab - b^2 - ac + bc) = 0$. $c^2 - 2ac + a^2 - 4ab + 4b^2 + 4ac - 4bc = 0$. $a^2 + 4b^2 + c^2 + 2ac - 4ab - 4bc = 0$. This can be written as $(a - 2b + c)^2 = 0$. Therefore,$a - 2b + c = 0$,which implies $a + c = 2b$. This is the condition for $a, b, c$ to be in Arithmetic Progression.

If the roots of the equation $(b - c)x^2 + (c - a)x + (a - b) = 0$ are equal,then $a, b, c$ are in which progression?

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