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(C) The month of November has $30$ days. The total number of outcomes is $n(S) = 30$.Let $A$ be the event that the date is a multiple of $5$. The mult

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$1/3$

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(C) The month of November has $30$ days. The total number of outcomes is $n(S) = 30$.Let $A$ be the event that the date is a multiple of $5$. The multiples of $5$ in ${1, 2, ..., 30}$ are ${5, 10, 15, 20, 25, 30}$. So,$n(A) = 6$.Let $B$ be the event that the date is a multiple of $6$. The multiples of $6$ in ${1, 2, ..., 30}$ are ${6, 12, 18, 24, 30}$. So,$n(B) = 5$.The intersection $A \cap B$ contains dates that are multiples of both $5$ and $6$ (i.e.,multiples of $30$). Thus,$A \cap B = {30}$,and $n(A \cap B) = 1$.Using the addition rule for probability: $P(A \cup B) = P(A) + P(B) - P(A \cap B) = \frac{6}{30} + \frac{5}{30} - \frac{1}{30} = \frac{10}{30} = \frac{1}{3}$.

$S.No.$	Name	Sex	Age in years
$1.$	Harish	$M$	$30$
$2.$	Rohan	$M$	$33$
$3.$	Sheetal	$F$	$46$
$4.$	Alis	$F$	$28$
$5.$	Salim	$M$	$41$

$A$ doctor schedules an appointment for a patient in the month of November. What is the probability that the date is a multiple of $5$ or $6$?

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