For an event,the odds against are $6 : 5$. The probability that the event does not occur is
- A$\frac{5}{6}$
- B$\frac{6}{11}$
- C$\frac{5}{11}$
- D$\frac{1}{6}$
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Similar Questions
The odds against a certain event are $5: 2$ and the odds in favour of another independent event are $6: 5$. The probability that at least one of the events will happen,is
One of the two events must occur. If the chance of one is $\frac{2}{3}$ of the other,then the odds in favour of the other are
Medium
View SolutionLet $A$ and $B$ be two events such that $P(A) = 0.3$ and $P(A \cup B) = 0.8$. If $A$ and $B$ are independent events,then $P(B) = $
Fill in the blanks in the following table:
$P(A)$ $P(B)$ $P(A \cap B)$ $P(A \cup B)$ $\frac{1}{3}$ $\frac{1}{5}$ $\frac{1}{15}$ $........$
| $P(A)$ | $P(B)$ | $P(A \cap B)$ | $P(A \cup B)$ |
| $\frac{1}{3}$ | $\frac{1}{5}$ | $\frac{1}{15}$ | $........$ |
Easy
View SolutionIf the odds in favour of an event be $3 : 5$,then the probability of non-occurrence of the event is
Easy
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