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(A) The total number of outcomes when two dice are thrown is $n(S) = 6 	imes 6 = 36$. The favorable outcomes for getting a sum of $7$ are $E = \{(1,

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$5 : 1$

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(A) The total number of outcomes when two dice are thrown is $n(S) = 6 	imes 6 = 36$. The favorable outcomes for getting a sum of $7$ are $E = \{(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)\}$. The number of favorable outcomes is $n(E) = 6$. The number of unfavorable outcomes is $n(S) - n(E) = 36 - 6 = 30$. The odds against the event are given by the ratio of unfavorable outcomes to favorable outcomes: $30 : 6 = 5 : 1$.

When two dice are thrown once,find the odds against getting a sum of $7$ on the two dice.

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