The observations 29, 32, 48, 50, x, x + 2, 72 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given observations are $29, 32, 48, 50, x, x + 2, 72, 78, 84, 95$.Total number of observations $n = 10$,which is an even number.For an even nu

Vedclass · Accepted Answer

$62$

Vedclass · Answer

(B) The given observations are $29, 32, 48, 50, x, x + 2, 72, 78, 84, 95$.Total number of observations $n = 10$,which is an even number.For an even number of observations,the median is the arithmetic mean of the $\left(\frac{n}{2}\right)^{th}$ and $\left(\frac{n}{2} + 1\right)^{th}$ terms.Here,the $5^{th}$ term is $x$ and the $6^{th}$ term is $x + 2$.Median $= \frac{x + (x + 2)}{2} = 63$.$\frac{2x + 2}{2} = 63$.$x + 1 = 63$.$x = 62$.

$x_i$	$3$	$6$	$9$	$12$
$f_i$	$1$	$2$	$3$	$4$

The observations $29, 32, 48, 50, x, x + 2, 72, 78, 84, 95$ are arranged in ascending order. If their median is $63$,what is the value of $x$?

Similar Questions

If a variable takes the discrete values $\alpha - 4, \alpha - \frac{7}{2}, \alpha - \frac{5}{2}, \alpha - 3, \alpha - 2, \alpha + \frac{1}{2}, \alpha - \frac{1}{2}, \alpha + 5$ (where $\alpha > 0$),then the median is:

The median of $21$ observations is $40$. If each observation greater than the median is increased by $6$,what will be the new median of the observations?

Find the mean of the following frequency distribution:

$x_i$ $3$ $6$ $9$ $12$

$f_i$ $1$ $2$ $3$ $4$

Find the weighted mean of the first $n$ natural numbers,where the weights are equal to their squares.

If a man spends an equal amount of money to buy three types of pens at $5$ Rs/pen,$10$ Rs/pen,and $20$ Rs/pen,what is the average cost per pen?

Vedclass Test Series

Exam Paper Generator

Online Exam Module