In a frequency distribution,if the mean and median are $21$ and $22$ respectively,then what is the approximate mode?
- A$24$
- B$25.5$
- C$20.5$
- D$22$
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Similar Questions
The mode of the following frequency distribution is:
Class $0-5$ $5-10$ $10-15$ $15-20$ $20-25$ $25-30$ Frequency $(f_i)$ $3$ $4$ $7$ $11$ $2$ $5$
| Class | $0-5$ | $5-10$ | $10-15$ | $15-20$ | $20-25$ | $25-30$ |
| Frequency $(f_i)$ | $3$ | $4$ | $7$ | $11$ | $2$ | $5$ |
Difficult
View SolutionFind the mode of the following frequency distribution.
$x$ $4$ $5$ $6$ $7$ $8$ $f$ $6$ $7$ $10$ $8$ $3$
| $x$ | $4$ | $5$ | $6$ | $7$ | $8$ |
| $f$ | $6$ | $7$ | $10$ | $8$ | $3$ |
Easy
View SolutionThe sum of the absolute deviations is minimum when taken with respect to:
Find the mode of the following frequency distribution.
Class $1 - 10$ $11 - 20$ $21 - 30$ $31 - 40$ $41 - 50$ $f_i$ $5$ $7$ $8$ $6$ $4$
| Class | $1 - 10$ | $11 - 20$ | $21 - 30$ | $31 - 40$ | $41 - 50$ |
| $f_i$ | $5$ | $7$ | $8$ | $6$ | $4$ |
Difficult
View SolutionConsider the following frequency distribution:
Class $0-6$ $6-12$ $12-18$ $18-24$ $24-30$ Frequency $a$ $b$ $12$ $9$ $5$
If $\text{mean} = \frac{309}{22}$ and $\text{median} = 14$,then the value of $(a-b)^{2}$ is equal to $.....$
| Class | $0-6$ | $6-12$ | $12-18$ | $18-24$ | $24-30$ |
| Frequency | $a$ | $b$ | $12$ | $9$ | $5$ |
If $\text{mean} = \frac{309}{22}$ and $\text{median} = 14$,then the value of $(a-b)^{2}$ is equal to $.....$
DifficultJEE MAIN 2021
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