Find the median of the following frequency di | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the median,we first calculate the cumulative frequency $(c.f.)$:						Class			$f_i$			$c.f.$							$0 - 10$			$8$			$8$							$10 - 20$

Vedclass · Accepted Answer

$23$

Vedclass · Answer

(B) To find the median,we first calculate the cumulative frequency $(c.f.)$:						Class			$f_i$			$c.f.$							$0 - 10$			$8$			$8$							$10 - 20$			$30$			$38$							$20 - 30$			$40$			$78$							$30 - 40$			$12$			$90$							$40 - 50$			$10$			$100$			Here,$N = 100$,so $\frac{N}{2} = \frac{100}{2} = 50$.The cumulative frequency just greater than $50$ is $78$,which corresponds to the class interval $20 - 30$.Thus,the median class is $20 - 30$.Here,$l = 20$,$f = 40$,$F = 38$,and $h = 10$.Median $= l + \left( \frac{\frac{N}{2} - F}{f} ight) 	imes h$$= 20 + \left( \frac{50 - 38}{40} ight) 	imes 10$$= 20 + \left( \frac{12}{40} ight) 	imes 10$$= 20 + 3 = 23$.

Class	Frequency
$10-20$	$180$
$20-30$	$82$
$30-40$	$34$
$40-50$	$180$
$50-60$	$136$
$60-70$	$23$
$70-80$	$50$

Find the median of the following frequency distribution.

Class $0 - 10$ $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$

$f_i$ $8$ $30$ $40$ $12$ $10$

Similar Questions

The reciprocal of the mean of the reciprocals of $n$ observations is their

Which of the following averages is most affected by extreme observations?

Which formula is used to calculate the weighted mean?

Find the median for the following distribution:
Class Frequency
$10-20$ $180$
$20-30$ $82$
$30-40$ $34$
$40-50$ $180$
$50-60$ $136$
$60-70$ $23$
$70-80$ $50$

The average of $n$ numbers $x_1, x_2, x_3, ..., x_n$ is $M$. If $x_n$ is replaced by $x'$,then the new average is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Class	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$
$f_i$	$8$	$30$	$40$	$12$	$10$

Find the median of the following frequency distribution. Class $0 - 10$ $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$ $f_i$ $8$ $30$ $40$ $12$ $10$