If the mode of a distribution is 18 and the m | vedclass

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(C) We know the empirical relationship between mean,median,and mode is given by:$	ext{Mode} = 3 	imes 	ext{Median} - 2 	imes 	ext{Mean}$Given:$

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$22$

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(C) We know the empirical relationship between mean,median,and mode is given by:$	ext{Mode} = 3 	imes 	ext{Median} - 2 	imes 	ext{Mean}$Given:$	ext{Mode} = 18$$	ext{Mean} = 24$Substituting the values into the formula:$18 = 3 	imes 	ext{Median} - 2 	imes 24$$18 = 3 	imes 	ext{Median} - 48$$18 + 48 = 3 	imes 	ext{Median}$$66 = 3 	imes 	ext{Median}$$	ext{Median} = \frac{66}{3}$$	ext{Median} = 22$

$x$	$4$	$5$	$6$	$7$	$8$
$f$	$6$	$7$	$10$	$8$	$3$

If the mode of a distribution is $18$ and the mean is $24$,then what is the median?

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