For a distribution $x_1, x_2, \dots, x_{101}$ such that $x_1 < x_2 < x_3 < \dots < x_{100} < x_{101}$,the mean deviation of this distribution about a number $k$ is minimum. Then $k$ is equal to which of the following?

  • A
    $x_1$
  • B
    $x_{51}$
  • C
    $x_{50}$
  • D
    $\frac{x_1 + x_2 + \dots + x_{101}}{101}$

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