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(D) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{max})$ of emitted photoelectrons is given by: $K_{max} = h
u - \Ph

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increases linearly with the frequency of the incident light.

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(D) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{max})$ of emitted photoelectrons is given by: $K_{max} = h
u - \Phi$,where $h$ is Planck's constant,$
u$ is the frequency of incident light,and $\Phi$ is the work function of the metal.Since the stopping potential $(V_s)$ is related to the maximum kinetic energy by $K_{max} = eV_s$,we have: $eV_s = h
u - \Phi$.Rearranging for $V_s$,we get: $V_s = (h/e)
u - (\Phi/e)$.This equation represents a linear relationship between the stopping potential $(V_s)$ and the frequency $(
u)$ of the incident light,where the slope is $(h/e)$ and the intercept is $-(\Phi/e)$.Therefore,the stopping potential increases linearly with the frequency of the incident light.

The stopping potential required to reduce the photoelectric current to zero is . . . . . .

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