The work function of a material is 4.0 eV. T | vedclass

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(C) The work function $\Phi_0$ is given by $\Phi_0 = h 
u_0 = \frac{hc}{\lambda_{max}}$.Given $\Phi_0 = 4.0 \ eV$.Using the relation $\lambda_{max} =

Vedclass · Accepted Answer

$310$

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(C) The work function $\Phi_0$ is given by $\Phi_0 = h 
u_0 = \frac{hc}{\lambda_{max}}$.Given $\Phi_0 = 4.0 \ eV$.Using the relation $\lambda_{max} = \frac{1240 \ eV \cdot nm}{\Phi_0 \ (in \ eV)}$.Substituting the values: $\lambda_{max} = \frac{1240}{4.0} \ nm$.$\lambda_{max} = 310 \ nm$.Thus, the longest wavelength of light that can cause photoelectric emission is $310 \ nm$.

The work function of a material is $4.0 \ eV$. The longest wavelength of light that can cause the emission of photoelectrons from this material is approximately ....... $nm$.

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