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(A) The intensity of light $I$ at a distance $r$ from a point source is given by the inverse square law: $I \propto \frac{1}{r^2}$.Since the photoelec

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$r_2^2 : r_1^2$

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(A) The intensity of light $I$ at a distance $r$ from a point source is given by the inverse square law: $I \propto \frac{1}{r^2}$.Since the photoelectric current $I_p$ is directly proportional to the intensity of incident light,we have $I_p \propto I$.Therefore,$I_p \propto \frac{1}{r^2}$.For distance $r_1$,the current is $I_1 \propto \frac{1}{r_1^2}$.For distance $r_2$,the current is $I_2 \propto \frac{1}{r_2^2}$.Taking the ratio of the two currents:$\frac{I_1}{I_2} = \frac{1/r_1^2}{1/r_2^2} = \frac{r_2^2}{r_1^2}$.Thus,the ratio $(I_1 : I_2)$ is $r_2^2 : r_1^2$.

When the distance of a light source from a photocell is $r_1$,the photoelectric current is $I_1$. If the distance is $r_2$,the photoelectric current becomes $I_2$. The ratio $(I_1 : I_2)$ is .....

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