The figure shows the variation of photocurren | vedclass

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(C) In the photoelectric effect,the stopping potential depends only on the frequency of the incident radiation and the work function of the metal surf

Vedclass · Accepted Answer

$f_a = f_b = f_c = f_d$ and $I_a < I_b < I_c < I_d$

Vedclass · Answer

(C) In the photoelectric effect,the stopping potential depends only on the frequency of the incident radiation and the work function of the metal surface. Since all four curves intersect the potential axis at the same point (the same stopping potential),the frequency of all four radiations must be the same. Therefore,$f_a = f_b = f_c = f_d$.The saturation photocurrent is directly proportional to the intensity of the incident radiation. From the graph,the saturation current values are $I_a < I_b < I_c < I_d$. Therefore,the intensities follow the same order: $I_a < I_b < I_c < I_d$.

The figure shows the variation of photocurrent with anode potential for four different radiations. Let $I_a, I_b, I_c$ and $I_d$ be the intensities for the curves $a, b, c$ and $d$ respectively $[f_a, f_b, f_c$ and $f_d$ are frequencies respectively].

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