If N_2, O_2, H_2,and He are filled separately | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the ideal gas equation,$PV = nRT$,where $n = \frac{m}{M}$.At constant pressure and temperature,the rate of diffusion or filling is in

Vedclass · Accepted Answer

$H_2$

Vedclass · Answer

(C) According to the ideal gas equation,$PV = nRT$,where $n = \frac{m}{M}$.At constant pressure and temperature,the rate of diffusion or filling is inversely proportional to the molar mass $(M)$ of the gas according to Graham's Law,or simply,for a fixed volume and pressure,the gas with the lowest molar mass will occupy the space most rapidly due to higher molecular velocity.The molar masses are: $N_2 = 28 \ g/mol$,$O_2 = 32 \ g/mol$,$H_2 = 2 \ g/mol$,and $He = 4 \ g/mol$.Since $H_2$ has the lowest molar mass,it will fill the tube first.

If $N_2, O_2, H_2$,and $He$ are filled separately in four car tubes at the same pressure,which gas will fill first?

Similar Questions

The Kelvin temperature of an ideal gas is proportional to:

What is the average kinetic energy per molecule of an ideal gas in $SI$ units at $25 \, ^\circ C$?

Kinetic energy in $kJ$ of $280 \ g$ of $N_2$ at $27^{\circ} C$ is approximately $(R = 8.314 \ J \ mol^{-1} \ K^{-1})$

Which of the following represents the kinetic gas equation?

At $STP$,$0.5 \ mol$ of $H_2$ gas and $1 \ mol$ of $He$ gas:

Vedclass Test Series

Exam Paper Generator

Online Exam Module