A mixture of CO and N_2 gases of equal mass i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The molar mass of both $CO$ and $N_2$ is $28 \, g/mol$.Since the masses are equal,the number of moles $(n = \frac{mass}{molar \, mass})$ for both

Vedclass · Accepted Answer

$P_{N_2} = P_{CO}$

Vedclass · Answer

(A) The molar mass of both $CO$ and $N_2$ is $28 \, g/mol$.Since the masses are equal,the number of moles $(n = \frac{mass}{molar \, mass})$ for both gases will be equal.According to Dalton's Law of Partial Pressures,the partial pressure of a gas is directly proportional to its mole fraction $(P_i = x_i 	imes P_{total})$.Since the number of moles of both gases is equal,their mole fractions are equal $(x_{CO} = x_{N_2} = 0.5)$.Therefore,the partial pressures are equal: $P_{CO} = P_{N_2}$.

$A$ mixture of $CO$ and $N_2$ gases of equal mass is filled in a cylinder. What will be the ratio of their partial pressures?

Similar Questions

Dalton's law of partial pressure is not applicable for which of the following mixtures?

The ratio of rates of diffusion of oxygen and an unknown gas is $1:4$. The unknown gas is

The water having more dissolved $O_{2}$ is:

The behaviour of matter in different states is governed by various physical laws. According to you,what are the factors that determine the state of matter?

Internal energy of an ideal gas depends on

Vedclass Test Series

Exam Paper Generator

Online Exam Module