Which of the following statements is incorrec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electronic configuration of $Mg$ is $[Ne] 3s^2$ and $Al$ is $[Ne] 3s^2 3p^1$. Due to the stable fully-filled $s$-orbital,$Mg$ has a higher fir

Vedclass · Accepted Answer

The second ionization enthalpy of $Mg$ is higher than the second ionization enthalpy of $Na$.

Vedclass · Answer

(B) The electronic configuration of $Mg$ is $[Ne] 3s^2$ and $Al$ is $[Ne] 3s^2 3p^1$. Due to the stable fully-filled $s$-orbital,$Mg$ has a higher first ionization enthalpy than $Al$. Thus,statement $A$ is correct.$Na$ has configuration $[Ne] 3s^1$. After removing one electron,$Na^+$ attains a stable noble gas configuration $([Ne])$. Therefore,removing the second electron from $Na^+$ requires a very high amount of energy. Thus,the second ionization enthalpy of $Na$ is much higher than that of $Mg$. Statement $B$ is incorrect.$Na$ $([Ne] 3s^1)$ has a lower first ionization enthalpy than $Mg$ $([Ne] 3s^2)$ due to lower effective nuclear charge and less stable configuration. Statement $C$ is correct.$Mg^{2+}$ has a stable noble gas configuration $([Ne])$,so removing the third electron requires significantly more energy than removing the third electron from $Al^{2+}$ $([Ne] 3s^1)$. Statement $D$ is correct.

Which of the following statements is incorrect?

Similar Questions

Which of the following atoms has the highest first ionization energy?

The correct order of ionisation energy of $C$,$N$,$O$,and $F$ is

Amongst the elements with the following electronic configurations,which one of them may have the highest ionisation energy?

The first ionization energy (in $kJ / mol$) of $Na, Mg, Al$ and $Si$ respectively,are

The set representing the correct order of first ionisation potential is

Vedclass Test Series

Exam Paper Generator

Online Exam Module