$A$ cell is constructed by dipping a copper rod in $1\,M\,CuSO_4$ solution and a nickel rod in $1\,M\,NiSO_4$ solution. The standard reduction potentials of copper and nickel electrodes are $+0.34\,V$ and $-0.25\,V$ respectively. Calculate the $EMF$ of the cell. (in $,V$)
- A$0.83$
- B$1.06$
- C$0.59$
- D$0.49$
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Similar Questions
For the spontaneity of a cell,which of the following is correct?
Medium
View SolutionReduction potential of ions are given below:
$ClO_4^{-}$ $E^{\circ} = 1.19 \ V$ $IO_4^{-}$ $E^{\circ} = 1.65 \ V$ $BrO_4^{-}$ $E^{\circ} = 1.74 \ V$
The correct order of their oxidising power is:
| $ClO_4^{-}$ | $E^{\circ} = 1.19 \ V$ |
| $IO_4^{-}$ | $E^{\circ} = 1.65 \ V$ |
| $BrO_4^{-}$ | $E^{\circ} = 1.74 \ V$ |
The correct order of their oxidising power is:
DifficultJEE MAIN 2024
View SolutionElectrode potential of $Zn^{2+}/Zn$ is $-0.76\,V$ and that of $Cu^{2+}/Cu$ is $+0.34\,V$. The $EMF$ of the cell constructed between these two electrodes is ............ $V$.
MediumAIPMT 2001
View Solution$Cr_2O_7^{2-} + I^{-} \to I_2 + Cr^{3+}$
$E^0_{cell} = 0.79 \ V$
$E^0_{Cr_2O_7^{2-}} = 1.33 \ V$,$E^0_{I_2}$ is ........... $V$
$E^0_{cell} = 0.79 \ V$
$E^0_{Cr_2O_7^{2-}} = 1.33 \ V$,$E^0_{I_2}$ is ........... $V$
Medium
View SolutionThe standard electrode potential $(E^{\circ}_{M^{3+}/M^{2+}})$ for $V$,$Cr$,$Mn$,and $Co$ are $-0.26 \ V$,$-0.41 \ V$,$+1.57 \ V$,and $+1.97 \ V$,respectively. The metal ions which can liberate $H_2$ from a dilute acid are
DifficultJEE MAIN 2023
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