At $25^o C$,the molar conductivity of a $0.1 \, N \, CH_3COOH$ solution is $80 \, S \, cm^2 \, mol^{-1}$ and the molar conductivity at infinite dilution is $400 \, S \, cm^2 \, mol^{-1}$. What is the degree of dissociation $(\alpha)$ of $CH_3COOH$?

The following figure shows the dependence of molar conductance of two electrolytes on concentration. $\Lambda_m^0$ is the limiting molar conductivity. The number of incorrect statement$(s)$ from the following is $...........$
$(A)$ $\Lambda_m^0$ for electrolyte $A$ is obtained by extrapolation.
$(B)$ For electrolyte $B$,the $\Lambda_m$ vs $\sqrt{c}$ graph is a straight line with an intercept equal to $\Lambda_m^0$.
$(C)$ At infinite dilution,the value of the degree of dissociation approaches zero for electrolyte $B$.
$(D)$ $\Lambda_m^0$ for any electrolyte $A$ or $B$ can be calculated using $\lambda^0$ for individual ions.

If the molar conductivities (in $S \ cm^2 \ mol^{-1}$) of $NaCl$,$KCl$,and $NaOH$ at infinite dilution are $126$,$150$,and $250$,respectively,the molar conductivity of $KOH$ (in $S \ cm^2 \ mol^{-1}$) is

$A$ solution of concentration $C \ g \ equiv/L$ has a specific resistance $R$. The equivalent conductance of the solution is

The equivalent conductance of a monobasic acid at infinite dilution is $348 \, \Omega^{-1} \, cm^2 \, eq^{-1}$. If the resistivity of the solution containing $15 \, g$ of acid (molar mass $49 \, g \, mol^{-1}$) in $1 \, L$ is $18.5 \, \Omega \, cm$,what is the degree of dissociation of the acid? .............. $\%$

The molar conductivities of $KCl$,$NaCl$ and $KNO_3$ are $100$,$120$ and $90 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductivity of $NaNO_3$ would be .......... $S \ cm^2 \ mol^{-1}$.