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(C) The electrolysis of water follows the reaction: $2H_2O(l) \rightarrow 2H_2(g) + O_2(g)$.According to the stoichiometry,the molar ratio of $H_2$ ga

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$4.48$

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(C) The electrolysis of water follows the reaction: $2H_2O(l) ightarrow 2H_2(g) + O_2(g)$.According to the stoichiometry,the molar ratio of $H_2$ gas to $O_2$ gas produced is $2:1$.Since the volume of gas is directly proportional to the number of moles under the same conditions of temperature and pressure (Avogadro's Law),the ratio of volumes will also be $2:1$.Given volume of $O_2 = 2.24 \ dm^3$.Therefore,volume of $H_2 = 2 	imes 2.24 \ dm^3 = 4.48 \ dm^3$.

During the electrolysis of water,the volume of $O_2$ gas evolved is $2.24 \ dm^3$. Under the same conditions,what will be the volume of $H_2$ gas in $dm^3$?

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