In a conductivity cell,the electrodes are separated by a distance of $2 \ cm$ and have a cross-sectional area of $4 \ cm^2$. If the conductivity of pure water is $8 \times 10^{-7} \ S \ cm^{-1}$,then the resistance of the water is:

  • A
    $8.13 \times 10^{-7} \ \Omega$
  • B
    $6.78 \times 10^{-5} \ \Omega$
  • C
    $6.25 \times 10^{5} \ \Omega$
  • D
    $7.18 \times 10^{7} \ \Omega$

Explore More

Similar Questions

The equivalent conductances of $CH_3COONa$,$HCl$,and $CH_3COOH$ at infinite dilution are $91$,$426$,and $391 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively. What is the equivalent conductance of $NaCl$ at infinite dilution?

$A$ conductivity cell dipped in $0.05 \ M$ $KCl$ has a resistance of $600 \ \Omega$. If the conductivity is $0.0015 \ \Omega^{-1} \ cm^{-1}$,what is the value of the cell constant (in $cm^{-1}$)?

The conductivity of $0.012 \ M$ $NaBr$ solution is $2.67 \times 10^{-4} \ S \ cm^{-1}$. What is its molar conductivity?

Which is the conductivity of $0.02 \ M \ HCl$ solution if molar conductivity of the solution at $25^{\circ} C$ is $412.3 \ \Omega^{-1} \ cm^{2} \ mol^{-1}$?

The resistance of a conductivity cell containing $0.001 \ M$ $KCl$ solution at $300 \ K$ is $150 \ \Omega$. What is the cell constant if conductivity of $KCl$ solution is $1.5 \times 10^{-4} \ \Omega^{-1} \ cm^{-1}$ (in $cm^{-1}$)?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo