Which of the following is the correct decreas | vedclass

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(C) The correct decreasing order of bond angles is $NO_2^+ > NO_2 > NO_2^-$.$1$. $NO_2^+$ is a linear molecule with $sp$ hybridization and a bond angl

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$NO_2^+ > NO_2 > NO_2^-$

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(C) The correct decreasing order of bond angles is $NO_2^+ > NO_2 > NO_2^-$.$1$. $NO_2^+$ is a linear molecule with $sp$ hybridization and a bond angle of $180^{\circ}$. It has no lone pair on the central nitrogen atom.$2$. $NO_2$ has one unpaired electron on the nitrogen atom,which exerts less repulsion than a lone pair,resulting in a bond angle of approximately $134^{\circ}$.$3$. $NO_2^-$ has one lone pair on the nitrogen atom,which exerts strong repulsion on the bonding pairs,reducing the bond angle to approximately $115^{\circ}$.

Which of the following is the correct decreasing order of bond angles?

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