According to the Molecular Orbital Theory,whi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the Molecular Orbital Theory,the bond order of a molecule is calculated as: $Bond \ Order = \frac{1}{2} (N_b - N_a)$,where $N_b$ is t

Vedclass · Accepted Answer

$He_2$

Vedclass · Answer

(C) According to the Molecular Orbital Theory,the bond order of a molecule is calculated as: $Bond \ Order = \frac{1}{2} (N_b - N_a)$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.For $He_2$,the total number of electrons is $4$.The electronic configuration is: $\sigma_{1s}^2 \sigma_{1s}^{*2}$.Bond order $= \frac{2 - 2}{2} = 0$.$A$ bond order of $0$ indicates that the molecule is unstable and does not exist.

According to the Molecular Orbital Theory,which of the following does not exist?

Similar Questions

What is the number of electrons present in antibonding orbitals of $N_2$ molecule according to molecular orbital theory?

Which of the following diatomic molecular species has only $\pi$ bonds according to Molecular Orbital Theory?

The molecule/ion having paramagnetic nature and a bond order of $1.0$ is

Use molecular orbital theory to explain why the $Be_{2}$ molecule does not exist.

Explain the formation of $H_{2}$ and the energy level diagram of the $H_{2}$ molecule.

Vedclass Test Series

Exam Paper Generator

Online Exam Module