(B) The electronic configuration of $N_2$ molecule ($14$ electrons) is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^2 (\pi

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(B) The electronic configuration of $N_2$ molecule ($14$ electrons) is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\sigma 2p_z)^2$. Antibonding orbitals are those denoted with an asterisk $(*)$. These are $(\sigma^* 1s)^2$ and $(\sigma^* 2s)^2$. Total number of electrons in antibonding orbitals $= 2 + 2 = 4$.

Class 11 Chemistry Chemical Bonding and Molecular Structure Molecular orbital theory

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What is the number of electrons present in antibonding orbitals of $N_2$ molecule according to molecular orbital theory?

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A
$14$
B
$04$
C
$10$
D
$06$

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Chemical Bonding and Molecular Structure

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Molecular orbital theory

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What is the number of electrons present in antibonding orbitals of $N_2$ molecule according to molecular orbital theory?

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