The pair of species that has the same bond or | vedclass

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(A) The bond order is calculated using the formula: $Bond \ order = \frac{N_b - N_a}{2}$,where $N_b$ is the number of electrons in bonding molecular o

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$CO, NO^{+}$

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(A) The bond order is calculated using the formula: $Bond \ order = \frac{N_b - N_a}{2}$,where $N_b$ is the number of electrons in bonding molecular orbitals and $N_a$ is the number of electrons in antibonding molecular orbitals.For $CO$ ($6+8=14$ electrons): Bond order $= \frac{10-4}{2} = 3$.For $NO^{+}$ ($7+8-1=14$ electrons): Bond order $= \frac{10-4}{2} = 3$.Since both $CO$ and $NO^{+}$ have $14$ electrons,they have the same bond order of $3$.For other options:$NO^{-}$ ($16$ electrons,$BO=2$),$CN^{-}$ ($14$ electrons,$BO=3$).$O_2$ ($16$ electrons,$BO=2$),$N_2$ ($14$ electrons,$BO=3$).$O_2$ ($16$ electrons,$BO=2$),$B_2$ ($10$ electrons,$BO=1$).

The pair of species that has the same bond order in the following is

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