Observe the following molecules: C_2, N_2, O_ | vedclass

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(B) The correct statement is $(b)$.All these molecules $(C_2, N_2, O_2, F_2)$ are formed by the combination of atomic orbitals of the second period el

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They have same number of bonding molecular orbitals and same number of antibonding molecular orbitals

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(B) The correct statement is $(b)$.All these molecules $(C_2, N_2, O_2, F_2)$ are formed by the combination of atomic orbitals of the second period elements.In each case,the total number of atomic orbitals involved is $10$ ($5$ from each atom),which results in the formation of $5$ bonding molecular orbitals $(BMOs)$ and $5$ antibonding molecular orbitals $(ABMOs)$ in the molecular orbital diagram (considering the $1s$ shell).Therefore,they all possess the same number of bonding and antibonding molecular orbitals.

Observe the following molecules: $C_2, N_2, O_2, F_2$. Which one of the following statements is correct for the above molecules?

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