Match List-$I$ with List-$II$ and select the correct answer.
List-$I$ List-$II$
$1.$ Aniline $a.$ Used in the preparation of azo dyes
$2.$ Nitrobenzene $b.$ Sulpha drug
$3.$ Sulphanilamide $c.$ Solvent in Friedel-Crafts reaction
$4.$ Trinitrotoluene $d.$ Used as an explosive

  • A
    $1-a, 2-c, 3-b, 4-d$
  • B
    $1-a, 2-b, 3-c, 4-d$
  • C
    $1-c, 2-d, 3-a, 4-b$
  • D
    $1-d, 2-c, 3-b, 4-a$

Explore More

Similar Questions

Consider the following reaction sequence:
$p$-Nitrotoluene $\xrightarrow{P} Q$ $\xrightarrow{R} S$ $\xrightarrow{H_2O} T$
$S \xrightarrow{U} \text{Benzoic acid}$
Identify the correct statements from the following:
$(A) P = H_2/Pd, \text{ethanol}; R = NaNO_2/HCl; U = 1. H_3PO_2, 2. KMnO_4-KOH, \text{heat}$
$(B) P = Sn/HCl; R = HNO_2; S = p-\text{toluenediazonium chloride}$
$(C) S = p-\text{toluenediazonium chloride}; T = p-\text{cresol}; U = 1. CH_3CH_2OH, 2. KMnO_4-KOH, \text{heat}$
$(D) Q = p-\text{nitrobenzoic acid}; R = H_2/Pd, \text{ethanol}; T = p-\text{cresol}$
Which of the following combinations is correct?

From $6.55 \ g$ of aniline,the maximum amount of acetanilide that can be prepared will be _ $\times 10^{-1} \ g$.

An organic compound $A$ contains nitrogen and chlorine. It dissolves readily in water to give a solution that turns litmus red. Titration of compound $A$ with standard base indicates that the molecular weight of $A$ is $131 \pm 2$. When a sample of $A$ is treated with aqueous $NaOH$,a liquid separates which contains $N$ but not $Cl$. Treatment of the obtained liquid with nitrous acid followed by phenol gives an orange precipitate. The compound $A$ is:

Arrange the following:
$(i)$ In decreasing order of the $pK_{b}$ values:
$C_{2}H_{5}NH_{2}, C_{6}H_{5}NHCH_{3}, (C_{2}H_{5})_{2}NH$ and $C_{6}H_{5}NH_{2}$
$(ii)$ In increasing order of basic strength:
$C_{6}H_{5}NH_{2}, C_{6}H_{5}N(CH_{3})_{2}, (C_{2}H_{5})_{2}NH$ and $CH_{3}NH_{2}$
$(iii)$ In increasing order of basic strength:
$(a)$ Aniline,$p-$nitroaniline and $p-$toluidine
$(b)$ $C_{6}H_{5}NH_{2}, C_{6}H_{5}NHCH_{3}, C_{6}H_{5}CH_{2}NH_{2}$
$(iv)$ In decreasing order of basic strength in gas phase:
$C_{2}H_{5}NH_{2}, (C_{2}H_{5})_{2}NH, (C_{2}H_{5})_{3}N$ and $NH_{3}$
$(v)$ In increasing order of boiling point:
$C_{2}H_{5}OH, (CH_{3})_{2}NH, C_{2}H_{5}NH_{2}$
$(vi)$ In increasing order of solubility in water:
$C_{6}H_{5}NH_{2}, (C_{2}H_{5})_{2}NH, C_{2}H_{5}NH_{2}$

Match List-$I$ with List-$II$ :
List-$I$ List-$II$
$a$. Gabriel synthesis $i$. Benzaldehyde
$b$. Kolbe synthesis $ii$. Ethers
$c$. Williamson synthesis $iii$. Primary amines
$d$. Etard reaction $iv$. Salicylic acid

Choose the correct answer from the options given below :

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo