The ammonolysis of alcohol is represented by the reaction $xCH_3OH + yNH_3 \xrightarrow[Al_2O_3/ThO_2]{300-400^{\circ}C} \text{Products}$. The products formed are:
- A$CH_3NH_2$
- B$(CH_3)_2NH$
- C$(CH_3)_3N$
- D$A$ mixture of amines
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View SolutionMatch the reactions given in Column-$I$ with the statements given in Column-$II$.
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| Column-$I$ | Column-$II$ |
|---|---|
| $A$. Ammonolysis | $1$. Amine with lesser number of carbon atoms |
| $B$. Gabriel phthalimide synthesis | $2$. Detection test for primary amine |
| $C$. Hoffmann Bromamide reaction | $3$. Reaction of phthalimide with $KOH$ and $R-X$ |
| $D$. Carbylamine reaction | $4$. Reaction of alkyl-halides with $NH_3$ |
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