A nitrile X is treated with LiAlH_{4} to obta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The nitrile $X$ is $CH_{3}CN$ (acetonitrile or ethanenitrile).$2$. Reduction of $CH_{3}CN$ with $LiAlH_{4}$ gives $CH_{3}CH_{2}NH_{2}$ (ethan

Vedclass · Accepted Answer

$(CH_{3}COO^{-})(CH_{3}CH_{2}NH_{3}^{+})$

Vedclass · Answer

(C) $1$. The nitrile $X$ is $CH_{3}CN$ (acetonitrile or ethanenitrile).$2$. Reduction of $CH_{3}CN$ with $LiAlH_{4}$ gives $CH_{3}CH_{2}NH_{2}$ (ethanamine),which is $Y$ $(C_{2}H_{7}N)$.$3$. Acidic hydrolysis of $CH_{3}CN$ gives $CH_{3}COOH$ (ethanoic acid),which is $Z$.$4$. When $Y$ (an amine,$CH_{3}CH_{2}NH_{2}$) and $Z$ (a carboxylic acid,$CH_{3}COOH$) are mixed,an acid-base reaction occurs to form a salt: $CH_{3}COOH + CH_{3}CH_{2}NH_{2} \rightarrow CH_{3}COO^{-}CH_{3}CH_{2}NH_{3}^{+}$.$5$. Thus,the product is $(CH_{3}COO^{-})(CH_{3}CH_{2}NH_{3}^{+})$.

$A$ nitrile $X$ is treated with $LiAlH_{4}$ to obtain compound $Y$ $(C_{2}H_{7}N)$. In a separate reaction,$X$ is hydrolyzed in an acidic medium to obtain $Z$. The product obtained after mixing $Y$ and $Z$ will be:

Similar Questions

$CH_3CH_2CONH_2$ $\xrightarrow{Br_2 / KOH_{(aq)}} X$ $\xrightarrow{C_6H_5COCl} Y$. Which statement is true?

When $methyl$ $iodide$ is heated with $ammonia$,the product obtained is

The end product $C$ of the following reaction is $C_2H_5NH_2$ $\xrightarrow{HNO_2} A$ $\xrightarrow{PCl_5} B$ $\xrightarrow{NH_3 (alc.)} C$

The correct sequence of reactions involved in the following conversion is:

Number of structural isomers of $C_4H_{11}N$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module