Which of the following statements is not correct?
- AAmines form hydrogen bonds.
- BEthylamine has a higher boiling point than propane.
- CMethylamine is more basic than ammonia.
- DThe basicity of dimethylamine is less than that of methylamine.
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Similar Questions
Which of the following compounds does not give alcohol on reduction?
Medium
View SolutionThe final product $(IV)$ obtained in the reaction sequence
Toluene $\xrightarrow[{2. \ H^{+}}]{{1. \ KMnO_4/OH^{-}}} I$ $\xrightarrow{{SOCl_2}} II$ $\xrightarrow{{NH_3}} III$ $\xrightarrow{{OBr^{-}}} IV$ is
Toluene $\xrightarrow[{2. \ H^{+}}]{{1. \ KMnO_4/OH^{-}}} I$ $\xrightarrow{{SOCl_2}} II$ $\xrightarrow{{NH_3}} III$ $\xrightarrow{{OBr^{-}}} IV$ is
Difficult
View SolutionMatch the compounds given in Column-$I$ with the items given in Column-$II$.
Column-$I$ Column-$II$ $A$. Benzenesulphonyl chloride $1$. Zwitter ion $B$. Sulphanilic acid $2$. Hinsberg reagent $C$. Alkyl diazonium salts $3$. Dyes $D$. Aryl diazonium salts $4$. Conversion to alcohols
| Column-$I$ | Column-$II$ |
|---|---|
| $A$. Benzenesulphonyl chloride | $1$. Zwitter ion |
| $B$. Sulphanilic acid | $2$. Hinsberg reagent |
| $C$. Alkyl diazonium salts | $3$. Dyes |
| $D$. Aryl diazonium salts | $4$. Conversion to alcohols |
Medium
View SolutionThe amine formed from an amide by means of bromine and alkali has
Medium
View SolutionWhat product will be formed from the Hofmann exhaustive methylation of the following compound?
$CH_3-CH(CH_3)-CH_2-NH-CH_2-CH_2-CH_3 \xrightarrow[(i) CH_3I (excess), (ii) Ag_2O, (iii) \Delta]{} \text{Product}$
$CH_3-CH(CH_3)-CH_2-NH-CH_2-CH_2-CH_3 \xrightarrow[(i) CH_3I (excess), (ii) Ag_2O, (iii) \Delta]{} \text{Product}$
Medium
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